This program's aim is :
- when user inputs: abcd7123, output should be: a7b1c2d3.
- if no.of letters are more than numbers or vice verse then remaining substring of greater string should be followed. eg: if i/p=abc12345 then o/p=a1b2c345 or if i/p=abcd12 then o/p=a1b2cd
1 #include<iostream> 2 #include<ctype.h> 3 using namespace std; 4 void print_remain(char *,int); 5 void print(char *, char *,int); 6 int main() 7 { 8 char a[10]={},b[10]={},c[50]; 9 cout<<"Enter the string"; 10 cin>>c; 11 int len=strlen(c); 12 int i=len,l=-1,m=-1,n=0; 13 while(i) 14 { 15 if(isalpha(c[n])) 16 { 17 l++; 18 a[l]=c[n]; 19 } 20 else 21 { 22 m++; 23 b[m]=c[n]; 24 } 25 i--;n++; 26 } 27 28 i=len,l=0,m=0,n=0; 29 int len_a=strlen(a),len_b=strlen(b); 30 if(len_a==len_b) 31 print(a,b,len); 32 else if(len_a<len_b) 33 { 34 print(a,b,len_a); 35 print_remain(b,len_a); 36 } 37 else 38 { 39 print(a,b,len_b); 40 print_remain(a,len_b); 41 } 42 return 0; 43 } 44 void print(char *a, char *b, int i) 45 { 46 int j=0,k=0; 47 while(i) 48 { 49 cout<<a[j]<<b[k]<<" "; 50 j++;k++;i--; 51 } 52 } 53 void print_remain(char *str, int indx) 54 { 55 int i=strlen(str); 56 while(i-indx) 57 { 58 cout<<str[indx]; 59 indx++; 60 } 61 62 }